Question

Hey ! Here's a Math question to test you all !

If x+y=3 and x^2+y^2=15 then the value of (x-y)^2 will be ?

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Answer 1

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⏩Question : x + y = 3 ....(1)

x² + y² = 15........ (2)

To find : (x -y)²

⏩Using identity : (x + y)² = x² + y² + 2(xy)

putting value from (1) and (2)

⏩3² = 15 +2(xy)

⏩ xy = 15 - 9 /2 = -3

so value of (x - y)² = 15 - 2(-3) = 21

SO,
FINAL ANSWER IS 21

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Answer 2

x=3-y..........1
x^2+y^2=15
(3-y)^2+y^2=15
9+y^2-6y+y^2=15
2y^2-6y-6=0
y^2-3y-3=0
y^2-3y+y-3=0
y(y-3)+1(y-3)=0
(y+1)(y-3)=0
y=-1, y=3
x=3-y=3-(-1)=4
(x-y)^2=(4-3)^2=1^2=1