Question

hey....i am new user


help me help me please answer question no 3

Answer 1

First make factors of 288 ie

288 equal to 2into2into2into2into2into3into3

Then grouping the factor in triple.

We observe that if 288 is multiplied by 2into3 then its prime factors will exist in triple.

Thus, the required answer is 2into3, which is nothing but 6.

6 is the answer.

Hope you understand.