Question

hey im new here and im very very confused please help me please

Answer 1

Given Equation is (a + b)^2x^2 + 8(a^2 - b^2)x + 16(a^2 - b)^2 = 0.

It is in the form of ax^2 + bc + c = 0, we get

a = (a + b)^2, b = 8(a^2 - b^2), c = 16(a^2 - b^2).

Now,

We know that : 

D = b^2 - 4ac 

    = 64(a^2 - b^2)^2 - 4(a + b)^2 * 16(a- b)^2

    = 64(a^4 - 2a^2b^2 + b^4) - 64(a + b)^2 (a - b)^2

    = 64(a^4 - 2a^2b^2 + b^4) - 64(a^2 + b^2 + 2ab)(a^2 + b^2 - 2ab)

    = 64a^4 - 128a^2b^2 + 64b^4 - 64(a^4 - 2a^2b^2 + b^4)

    = 64a^4 - 128a^2b^2 + 64b^4 - 64a^4 + 128a^2b^2 - 64b^4

    = 0.


Therefore the value of D = 0.


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks