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Two taps A and B can together fill a tank in 15 days. Taps A and B are kept open for 12 days and then tap B is closed it takes another 8 days to fill a tank.
How many days does each tap require to fill a tank.
From lesson linear equation in two veriables.
nia34:
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QUESTION:
two taps A and B together fill a swimming pool i 15 days . Tap A and B are kept open for 12 days and then tap B is closed . It takes another 8 days for the swimming pool to be filled. How many days each tap require to fill the swimming pool?
ANSWER :
24 days.
EXPLANATION :
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Let A and B be the rates of the 2 taps.
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Equation:
15A + 15B = 1 job
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20A + 12B = 1 job
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Multiply thru the top equation by 12
multiply thru the bottom equation by 15
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180A + 180B = 12
300A + 180B = 15
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Subtract and solve for A
120A = 3
A = 1/40 job/day (A's rate)
A would take 40 days to fill the pool alone.
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Solve for "B"
20A + 12B = 1
1/2 + 12B = 1
12B = 1/2
B = 1/24 job/day (B's rate)
A would take 24 days to fill the pool alone.
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