Question

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Two taps A and B can together fill a tank in 15 days. Taps A and B are kept open for 12 days and then tap B is closed it takes another 8 days to fill a tank.
How many days does each tap require to fill a tank.

From lesson linear equation in two veriables. ​

Answer 1

Hey!
Solution...

Since, taps a and b fill the pool together in 15 days.

The amount of water filled by both the tap in 1 day = 1/15 of pool.

The water filled by both the taps in 12 days = 12/15 = 4/5.....The remaining = 1 - 4/5 = 1/5 of the pool

Now tap a fill 1/5 of the pool in 8 days.
Therefore, number of days in which tap "a" fill the pool = 8÷1/5 = 40days.

The water filled by tap "a" in 1 day = 1/40
The water filled by tap "b" in 1 day =
1/15 - 1/40
= 8-3/120
= 5/120
= 1/24

So, the number of days in which tap "b" will fill the pool is $\bold{24\:days}$.

Answer 2

hiiii,

Since taps a and b fill the pool together in 15 days.

the amount of water filled by both the tap in 1 day = 1/15 of pool

the water filled by both the taps in 12 days = 12/15 = 4/5

the remaining = 1 - 4/5

= 1/5 of the pool

now tap a fill 1/5 of the pool in 8 days.

therefore number of days in which tap "a" fill the pool = 81/5=40 days

the water filled by tap "a" in 1 day

= 1/40

the water filled by tap "b" in 1 day

= 115−140

=8−3120

=5120

=124

thus the number of days in which tap "b" fill the pool = 24 days

hope it helps you✌✌✌✌