hey koi phythogoras theorem bta do
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Heya !!
Here is your answer.
Theorem : In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Let ABC be a right angle triangle , right angled at B.
Construction : Draw perpendicular BD from B on AC.
Proof :
Triangle ADB ~ ABC,
==> AB/AC = AD/AB
==> AB^2 = AC . AD ------(i)
Triangle BDC ~ ABC,
==> BC/AC = CD/BC
==> BC^2 = AC . CD ------(ii)
Adding (i) & (ii) , we get
AB^2 + BC^2 = AC ( AD + CD )
AB^2 + BC^2 = AC^2 [AD + CD = AC]
PROVED.
Here is your answer.
Theorem : In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Let ABC be a right angle triangle , right angled at B.
Construction : Draw perpendicular BD from B on AC.
Proof :
Triangle ADB ~ ABC,
==> AB/AC = AD/AB
==> AB^2 = AC . AD ------(i)
Triangle BDC ~ ABC,
==> BC/AC = CD/BC
==> BC^2 = AC . CD ------(ii)
Adding (i) & (ii) , we get
AB^2 + BC^2 = AC ( AD + CD )
AB^2 + BC^2 = AC^2 [AD + CD = AC]
PROVED.
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thx dear
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