hey lady and gentleman online brainly person if ur free give my answer
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Area of a ||gm
= Base × corresponding height.
When we will take AB as base, then height would be DM
so, area = AB × DM
=> 12 × 8
= 96 cm²
Now when we will take BC as base, then height would become BN
The area would be same as the figure is same.
=> BC × BN = 96
=> BC × 14 = 96
=> BC = 96/14
=> BC = 48/7 cm
= 6.85 cm(approx)
= Base × corresponding height.
When we will take AB as base, then height would be DM
so, area = AB × DM
=> 12 × 8
= 96 cm²
Now when we will take BC as base, then height would become BN
The area would be same as the figure is same.
=> BC × BN = 96
=> BC × 14 = 96
=> BC = 96/14
=> BC = 48/7 cm
= 6.85 cm(approx)
Answered by
2
HII MATE!!
GIVEN-->ABCD IS IIGM,AB=12cm ALTITUDE CORRESPONDING TO SIDE AB AND AD IS DM=8cm,BN=14cm.
TO FIND-->BC
AS THE BASE IS AB AND HEIGHT IS DM
AREA OF IIGM ABCD = base×height
=AB×DM
=12×8
=96cm^2
Taking BC AS THE BASE AND BN AS THE HEIGHT,
AREA OF IIGM=base×height
96= BC×BN
96=BC×14
BC=96÷14
=6.8571cm
Thanks
I THINK IT HELPS....
@garu1678
GIVEN-->ABCD IS IIGM,AB=12cm ALTITUDE CORRESPONDING TO SIDE AB AND AD IS DM=8cm,BN=14cm.
TO FIND-->BC
AS THE BASE IS AB AND HEIGHT IS DM
AREA OF IIGM ABCD = base×height
=AB×DM
=12×8
=96cm^2
Taking BC AS THE BASE AND BN AS THE HEIGHT,
AREA OF IIGM=base×height
96= BC×BN
96=BC×14
BC=96÷14
=6.8571cm
Thanks
I THINK IT HELPS....
@garu1678
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