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3√2 x^2 + 13x + 6√2
3√2 x^2 + 9 x + 4x + 6√2
3x( √2x + 3) + 2√2( √2x + 3)
(3x +2√2)( √2 x + 3)
zeroes
3x= -2√2
x= -2√2/3
√2x +3 = 0
√2x = -3
x= -3/√2
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HEYA.......✌✌✌✌
HERE IS YOUR ANSWER............
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