Math, asked by swetharosy25, 1 year ago

hey mate please answer to this question don't spam ​

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Answered by Anonymous
3

3√2 x^2 + 13x + 6√2

3√2 x^2 + 9 x + 4x + 6√2

3x( √2x + 3) + 2√2( √2x + 3)

(3x +2√2)( √2 x + 3)

zeroes

3x= -2√2

x= -2√2/3

√2x +3 = 0

√2x = -3

x= -3/√2

Answered by gmamadhumita3
2

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HERE IS YOUR ANSWER............

Plz refer the solution

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