Hey mate please solve this...
Answers
Answer:
HEY MATE HERE IS YOUR ANSWER :
The area of tin sheet required to make the funnel 2376 sq cm
Step-by-step explanation:
Given :
Radius (R) of upper circular end of frustum part = 36/2 = 18 cm
Radius (r) of lower circular end of frustum part = Radius of circular end of cylindrical part = 20/2 = 10 cm
Height (h1) of frustum part = 29 – 14 = 15 cm
Height (h2) of cylindrical part = 14 cm
Slant height (l) of frustum part
= √(R–r)² + h²
= √(18–10)² + (15)²
= √(8)² + 225
= √64 + 225
= √289
= 17 cm
Area of tin sheet required = curved surface area of frustum + curved surface area of cylinder
Area of tin sheet required
= π(R + r)× l + 2πr h2
= 22/7 × (18 + 10) × 17 + 2× 22/7 × 10 × 14
= 22/7 × 28 × 17 + 22/7 × 20 × 14
= 22 × 4 × 17 + 22 × 20 × 2
= 22 × 68 + 22 × 40
= 1496 + 880
= 2376 sq cm
since, the area of tin sheet required is 2376 sq cm
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