Question

hey mate plz help me​

Answer 1

Answer:

speed(v) = 144km/hr = 40m/s

acceleration(a)= v/t = 40/20= 2m/s^2

distance (s) = 1/2at^2 ( as initial velocity u = 0)

= 1/2×2×20×20

= 400 metres

Therefore, the distance car covers is 400 metres.

Answer 2

answer:400m

speed=144km/h

=144×5/18=40m/s v=u+at

apply,

v=u+at=40m/s

v=40m/s

u=0m/s

a=?

t=20s

40=0+20×a

a=2m/s²

apply,

s=ut+1/2at²

s=?

u=0m/s

a=2m/s²

t=20s

s=0+2×20²/2

s=400m

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