Math, asked by Alifaa, 1 year ago

Hey mate plz solve it...
X²-Y²+6Y-9

Answers

Answered by siddhartharao77
4

Step-by-step explanation:

Given Equation is x² - y² + 6y - 9

= x² - (y² - 6y + 9)

= x² - (y² - 2 * 3 * y + 3²)

= x² - (y - 3)² {∵ a² - 2ab + b² = (a - b)²}

= (x - y + 3)(x + y - 3)

Hope it helps!

Answered by Siddharta7
0

x²-y²+6y-9

= x² - (y²-6y+9)

= x² - (y²-2*x*3+3²)

= x²- (y-3)²

\boxed { a^{2}-2ab+b^{2}=(a-b)^{2}}

= [x+(y-3)][x-(y-3)]

\boxed {x^{2}-y^{2}=(x+y)\times(x-y)}

= (x+y-3)(x-y-3)

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