Question

Hey Mates !

Find the zeroes of polynomial

${x}^{3} - {x}^{2}$


NO SPAMMING!

TSRJC - CET Entrance Test - 2018

Answer 1

Hey mate !!

Here's the answer !!

Given :

x³ - x² is a polynomial.

To find :

Zeros of that polynomial

Proof :

We know that,

For a polynomial to be having zeros it must be equated with some constant.

But since the constant is missing here, we tend to take the polynomial to be equated with zero itself. So,

= x³ - x² = 0

=> x ( x² - x ) = 0

=> x = 0, x² - x = 0

= x² = x

 => x = + √ x , - √ x

So x can be 0 as well as √ x , - √ x

Hope my answer helped !!

Cheers !!

Answer 2

Answer:

$\huge\orange{❥︎❥︎ANSWER}$

According to your question we have to find the zeros of polynomial

$x {}^{3 } - x {}^{2}$

We have to prove that :

$x {}^{3} - x {}^{2} = 0 \\ therefore \: x(x {}^{2} - x) = 0 \\ therefore \: x = 0 \: x {}^{2} - x = 0 \\ therefore \: x {}^{2} = x \\ so \: x = 1$

Step-by-step explanation:

Hope it is helpful to you..

$\huge\orange{❥︎</strong><strong>❥︎THANK</strong><strong> </strong><strong>YOU</strong><strong>}$☺️