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![Prove \: that \:if \: x \: and \: y \: are \: both \: odd \: positive \: integers \: \\ , then \: {x}^{2}+ {y}^{2} \: is \: even \: but \: not \: divisble \: by \: 4 Prove \: that \:if \: x \: and \: y \: are \: both \: odd \: positive \: integers \: \\ , then \: {x}^{2}+ {y}^{2} \: is \: even \: but \: not \: divisble \: by \: 4](https://tex.z-dn.net/?f=Prove+%5C%3A+that+%5C%3Aif+%5C%3A+x++%5C%3A+and++%5C%3A+y+%5C%3A++are++%5C%3A+both++%5C%3A+odd+%5C%3A++positive+%5C%3A++integers+%5C%3A+++%5C%5C+%2C+then++%5C%3A+%7Bx%7D%5E%7B2%7D%2B++%7By%7D%5E%7B2%7D++%5C%3A+is+%5C%3A+even+%5C%3A+but+%5C%3A+not+%5C%3A+divisble+%5C%3A+by+%5C%3A+4)
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Hii mate here is Your Answer,
Given :- X and Y are odd positive integers so it can be written as follows :-
x = 2m +1 and y = 2m +1 ( format of odd no.)
=> x^2 + y^2 = (2m +1)^2 + (2m + 1)^2
=> (4m^2 + 4m + 1) + (4m^2 + 4m + 1)
=> 8m^2 + 8m + 2
•From this number only 2 can be taken common as 2( 4m^2 + 4m + 1 ) but 4 cannot be taken common.
• as it is divisible by 2 it is an even no. but not divisible by 4 .....(Ans.)
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