◦•●◉✿HEY MATES✿◉●•◦
I'm actually not getting a clear calculation for this question.
Can you guys please help me?
⏩Do solve it step wise.
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Answered by
1
let a = i
b = i + j + k
a.b = 1
=> 1.√3.cos@ = 1
=> cos@ = 1/√3
so , OPTION A
(use dot product)
b = i + j + k
a.b = 1
=> 1.√3.cos@ = 1
=> cos@ = 1/√3
so , OPTION A
(use dot product)
Answered by
2
Explanation:
A vector =i^
B vector =i^+j^+k^
A vector×B vector=1
[(1)^1/2]×[(1+1+1)^1/2cos θ]=1
(1^1/2)×3^1/2 cosθ=1
1×√3cosθ=1
θ=cos^-1(1/√3)
It is cross product
Option A is answer
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