Question

hey mates



if x+y=10

find
$\frac{ {x}^{2} }{ {y}^{3} }$
​

Answer 1

⠀⠀⠀⠀⠀⠀$\huge{ \underline{ \red{ \bold{ \underline{ \bf{AnSweR }}}}}}$

given:-

x+y=10

x=10-y-------------1

$\frac{ {x}^{2} }{y {}^{3} } .........2$

substituting equation 1 in 2

Now,

$\frac{(10 - y) {}^{2} }{ {y}^{3} }$

when the quotient of the expression =0 ,then the numerator has to be 0.

so,

$(10 - y) {}^{2} = 0 \\ 10 - y = 0 \\ - y = - 10 \\ y = 10$

Putting value of y in 1.

x=10-10

x=0

Answer 2

Answer :

x = 10

y = 0

x^2/y^3 = (10)^2/0^3 = 100