Chemistry, asked by superwoman207, 1 year ago

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Answered by mrunal26
5

Hey mate

Here is your answer

(a) C12H22O11----->12C + 11H2O

(b) 2NaBr + 2H2SO4

------> Br2 + Na2So4 + So2 +2H2O

(c)2Kcl + H2So4----->2HCl + K2So4

(d) Cu + 2H2So4

------>CuSo4 + So2 + H2o

(e) 3S + 2H2So4------>3So2 + 2H2o

Answered by Anonymous
0

Thanks for question!!

Given H2SO4 is added on 4 test tube having :-

1) cane sugar

2)Sodium bromide

3) Copper turnings

4) Sulphur

Q.1. Formation of black substance.

Ans:- When conc. H2SO4 is react with cane sugar it act as dehydrating agent which removes water from cane sugar and give it black colour this is highly exothermic reaction.

*C12H22O11 (sugar) + H2SO4 (sulfuric acid) → 12 C (carbon) + 11 H2O (water) + mixture of water (black ).

Q.2.Evolution of brown gas?

Ans:- When conc. H2SO4 is added with sodium bromide it oxidised bromine with evolution of brown gas .

Reaction:-

2NaBr+2H2SO4→Na2SO4+Br2+SO2+2H2O .

Q.3.Evolution of colourless gas?

Ans:- When conc.H2SO4 react with sulphur it get oxidised and reduced to form a colourless gas of SO2.

*S (s) + 2H2SO4 (l) → 3SO2 (g) + 2H2O (l)

Q.4.Formation of brown substance which on dillution become blue?

Ans:- When conc. H2SO4 is react with copper turnings it form CuSO4 which is blue in colour.

2H2SO4 + Cu (s) → CuSO4 + SO2 + 2H2O.

Q.5.Disappearance of yellow colour and formation of colourless gas?

Ans:- when conc. H2SO4 react with sulphur the yellow colour of sulphur get faded away with the formation of colourless SO2 gas.

*S (s) + 2H2SO4 (l) → 3SO2 (g) + 2H2O (l)

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