Question

hey mates
please answer this question
quality answers will be marked as brainliest
orelse reported
once again saying only quality answers with brief explanation will be marked as brainliest​

Answer 1

AnswEr :

From the Question,

• m₁ = 10 Kg
• m₂ = 4 Kg
• m₃ = 2 Kg

Total mass of the system would be : 10 + 4 + 2 = 16 Kg

Here,

F₁ & sine of F₂ are acting downwards and F₃ is acting upwards.

Thus, Net Force and Acceleration are pointing downwards.

Now,

• F₁ = m₁g = 10g N

• F₂ = F₂sin(30) = 4g × 1/2 = 2g N

• F₃ = m₃g = 2g N

Therefore,

Net Force = F₁ + F₂ - F₃

$\longrightarrow$ Net Force = 10g N

$\longrightarrow$ Ma = 10g

$\longrightarrow$ 16a = 10 g

$\longrightarrow$ a = 5g/8

Acceleration of the system is 5g/8.

Answer 2

Given :

1. $\sf m_1$ = 10 kg
2. $\sf m_2$ = 4 kg
3. $\sf m_3$ = 2 kg

To find :

• AcceIeration of system

SoIution :

At first we need to find force on seperate bIocks i.e. $\sf m_1, \ \sf m_2, \ \sf m_3$ :

AppIying 2nd Iaw of Newton :

$\longmapsto\sf Force = Mass \times AcceIeration$

$\longmapsto\sf F_1 = mg = 10 \times g = 10g \ N$

$\longmapsto\sf F_2 = mg\sin\theta \\ \longmapsto\sf F_2 = 4 \times \ g \times \sin 30 \degree \\ \longmapsto\sf F_2 = 4 \times \ g \times (1/2) \\ \longmapsto\sf F_2 = 2g \ N$

$\longmapsto\sf F_3 = mg = 2 \times g = 2g \ N$

Now net force = $\sf F_1 + F_2 - F_3$

Again net force, $\sf F_{net}$ = $(\sf m_1 + m_2 + m_3) \times a$

⇒ 10g + 2g - 2g = (10 + 4 + 2) × a

⇒ 10g = 16a

⇒ a = 10g/16

⇒ a = 5g/8 m/s²

∴ Correct option : 3)5g/8 m/s²