hey mates please solve these questions.
question 5 and 7 it's urgent please solve this.
please it's urgent
refrain from posting meaningless answer otherwise it will be reported
Answers
Answer:
Step-by-step explanation:
Note: For question 5, since i donot have m in brainly superscript, I am using x.
5) 49ⁿ⁺¹ * 7ⁿ - (343)ⁿ / 7³ˣ * 2⁴ = 3/343
=> (49)ⁿ * 49 * 7ⁿ - (7³)ⁿ / 7³ˣ * 16 = 3 / 343
=> (7²)ⁿ * 7ⁿ * 49 - (7³)ⁿ / 7³ˣ * 16 = 3 / 343
=> 7²ⁿ * 7ⁿ * 49 - 7³ⁿ / 7³ˣ * 16 = 3 / 343
=> 7²ⁿ⁺ⁿ * 49 - 7³ⁿ/ 7³ˣ * 16 = 3/343
=> 7³ⁿ * 49 - 7³ⁿ / 7³ˣ * 16 = 3/343
//7³ⁿ can be taken as common in numerator on left hand side.
=> 7³ⁿ[ 49 - 1] / 7³ˣ . 16 = 3/343
=> 7³ⁿ * 48 / 7³ˣ . 16 = 3/343
//Since 16 * 3 = 48
=> 7³ⁿ * 3 / 7³ˣ = 3/343
//3 on both sides cancels out
=> 7³ⁿ⁻³ˣ = 1/343
=> 7³ⁿ⁻³ˣ = 7⁻³
//when bases are same powers are equal
=> 3(n - x ) = - 3
=> n - x = - 1
=> x = n + 1 ( Please replace m in place of x everywhere above)
7. (b³c⁻²/b⁺⁴c³)⁻³ ÷ (b⁻¹c/b²c⁻²)⁵ = bˣcᵃ ( considering a instead of y)
Let us first solve L.H.S:
(b³ * b⁴ / c³ * c²)⁻³ ÷ (c * c²/ b² * b)⁵
=> [(b⁷/c⁵)⁻³] ÷ [(c³/b³)⁵]
=> [1 / (b⁷/c⁵)³] ÷ [(c³/b³)⁵]
=> [1 / (b²¹/c¹⁵)] ÷ [(c¹⁵/b¹⁵)]
=> [c¹⁵/b²¹] ÷ [(c¹⁵/b¹⁵)]
=> [c¹⁵ / b²¹] * [b¹⁵/c¹⁵]
=> c¹⁵⁻¹⁵ / b²¹⁻¹⁵
=> c⁰/b⁶
=> b⁻⁶c⁰
Now,
b⁻⁶c⁰ = bˣcᵃ ( Please substitute a with y)
=> x = - 6, a = 0
x + a + 6 = - 6 + 0 + 6 = 0
Hence proved.