hey mates plz solve this........
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Explanation:
consider this to be a case of a simply supported beam AB. the supports being at both the end points and let the length of the beam be 1.8m.
assume the weight of the car to be a point load acting at a distance of 1.05m from poi t B.
applying the laws of equilibrium,
summation of all forces in the vertical direction gives F(A) + F(B)=1800...1
also moment balance at point A gives
1800*0.75=F(B)*1.8....2
F(B)= 750Kg
so
F(A)=1050Kg
the load on each front tyre is 750/2=375kg
the load on each back tyre is 1050/2=525kg.
hence solved
2700=1.8B
B= 1500kg
A= 300kg
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