Question

hey mates plzz solve question no. 1

Answer 1

Answer :-
©Case 1 ©
when Ani is older than Biju

Let age of
Biju = X
Ani = X + 3
Dharam (Ani's father) = 2(X+3)
Cathy (Biju's sister)= 1/2 X

Now as given that
Dharam's age - Cathy's age = 30

or
2X + 6 - 1/2X = 30
=> 1.5 X = 30 - 6
=> 1.5 X = 24
or X = 24/ 1.5
= 24/3 × 2
= 16
so age of Biju = X = 16
And age of Ani = X + 3 = 19



©Case 2 ©
When Biju is older than Ani

Let age of
Ani = Y
Biju = Y+3
Dharam (Ani's father ) = 2Y
Cathy ( Biju's sister) = (Y+3)/2

Now as Given

Dharam's age - Cathy's age = 30

or

2Y - (Y+3)/2 = 30
=>(4Y - Y + 3)/2 = 30
=> 3Y + 3 = 60
=> 3Y = 57
=> Y = 19

Now

Ani's age = Y = 19

and

Biju's age = Y+3 = 22

So possible ages of

Ani = 19 in CASE 1
= 19 in CASE 2

Biju = 16 in CASE 1
= 22 in CASE 2

HOPE IT HELPS ^_^

Answer 2

Sol)
The difference between the ages of Biju and Ani is 3 years.

Either Biju is 3 years older than Ani or Ani is 3 years older than Biju. However, it is obvious that in both cases.

Ani’s father’s age will be 30 years more than that of Cathy’s age.

Let the age of Ani and Biju be x and y years respectively.

Therefore, age of Ani’s father, Dharam = 2 × x = 2x years

And age of Biju’s sister Cathy  = y / 2 years

Case (i) :When Ani is older than Biju by 3 years,

x − y = 3 …...............(i)

2x – y / 2 = 30

4x − y = 60 …...............(ii)

Subtracting (i) from (ii), we obtain

3x = 60 − 3 = 57

x = 57 / 3 = 19

Therefore, age of Ani = 19 years

And age of Biju = 19 − 3 = 16 years

Case (ii) :When Biju is older than Ani,

y − x = 3 …........ (I)

2x – y / 2 = 30

4x − y = 60 …...............(ii)

Adding (i) and (ii), we obtain

3x = 63

x = 21

Therefore, age of Ani = 21 years