hey mates. plzzz answer this. i will mark u as brainliest. The mass of a boy is 20kg and the area of the sole of his foot is 0.01m2 . If g=10m/s 2, calculate the pressure exerted on the floor when he is standing on his
i) both feet
ii) one foot.
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We know that,,
<b > <i > <marquee > Pressure=Force/Area
And Force = mass×acceleration
=mg =20×10=200N
i) When boy is standing on both feet, The area will be twice the area of the sole of his foot
=2×0.01
=0.02m²
So pressure =F/A
=200/0.02
=2×10²/2×10^-2
=10^4 Pascal=10000Pascal
ii) When boy is standing on one foot...
Force =200N
Area=0.01m²
Pressure = 200/0.01
=2×10²/10^-2
=2×10^4 Pascal≡20000Pascal
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