Question

HEY MATHS EXPERT'S AND GENIUS.

CAN ANYONE ANSWER THIS ATTACHMENT

Answer 1

tan48 tan 23 tan60 tan(90-48) tan(90-23)

tan48 cot48 tan23 cot23 tan 60

1*1*tan 60

tan 60

root 3

Answer 2

Step-by-step explanation:

Given, tan48° tan23° tan60° tan42° tan67°

= tan(90° - 42°)tan(90° - 67°)tan60°tan42°tan67°

= cot 42° cot 67° (√3) tan 42° tan 67°

= (cot 42° tan 42°)(√3)(cot 67° tan 67°)

∴ tanθ = (1/cotθ)

= (cot 42 * 1/cot 42°)(√3)(cot 67° * 1/cot 67°)

= (1)(√3)(1)

= √3.

Hope it helps!