hey maths genius answer 5th question please....
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ans is no....cuz always the last digit will be 1, 6
eg: 6¹= 6
6²=36.
6³= 216
6ⁿ= __6
eg: 6¹= 6
6²=36.
6³= 216
6ⁿ= __6
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if the number 6 ^ n for any n ,were to end with the digit 0 then it would be divisible by 5. that is the prime factorisation of 6^ n would contain the prime 5.but 6^ n=(2*3)^ n = 2^ n* 3^ n so the primes in factorisation of 6^ n are 2 and 3. So the uniqueness of F.T.A guarantees that no other prime except 2 & 3 in factorisation of 6^ n .so there is no natural number n for which 6 ^ n ends with digit 0 .
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