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A body 'A' is dropped from a height 'h' and the outer body 'B' is thrown horizontally with a velocity of 10 ms -1 from the same height simultaneously. If the time taken by the body A to reach the ground in 3 s, find the velocity of the body 'B', in vertical direction when it is at a height of 20 m above the ground.
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Time taken for body A to reach ground is 3sec
h=0.5gt2=0.5*10*9= 45 meters.
Body B is thrown from height h=45m with Horizontal velocity =10 m/s
at height h=20m, uy=?
uy=g.tt is the time taken for the body to reach 20m height h=45−20=25mh=12gt2t=2h/g‾‾‾‾√=2*15/10‾‾‾‾‾‾‾‾‾√t=3‾√=1.73secuy=10*1.73=17.3 m/sec
h=0.5gt2=0.5*10*9= 45 meters.
Body B is thrown from height h=45m with Horizontal velocity =10 m/s
at height h=20m, uy=?
uy=g.tt is the time taken for the body to reach 20m height h=45−20=25mh=12gt2t=2h/g‾‾‾‾√=2*15/10‾‾‾‾‾‾‾‾‾√t=3‾√=1.73secuy=10*1.73=17.3 m/sec
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