Question

Solve the following initial value problem using undetermined coefficient method: d^2y/dx^2 − 4(dy/dx) + 3y = 9x^2 + 4​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

your answer is ⤵️

PT = y√(1+ cot2 θ )=y√(1+(dx/dy)2 ). Also, PN = y sec q = y√(1+tan2 θ )=y√(1+(dy/dx)2 ). => Length of the normal, PN = |y| √(1+(dy/dx)2 )......