Question

Hey people !!
Hope all of u r doing great !! plz answer my question ASAP!

Find the point on X-axis that is equidistant from (2,5) and (-2,9) .

I need the answer with process!!
thanks in advance.​

Answer 1

Step-by-step explanation:

$\\ \huge \: hey....$

Let..

(2, 5) = (x1, y1)

(-2, 9) = (x2, y2)

See, point which we have to find is equidistant to both of them

(x-2)^2 + (y-5)^2 = (x+2)^2 +(y-9) ^2

x^2 +4 -4x +y^2 +25 -10y

= x^2 +4 -4x + y^2 +81 -18y

25 -10y = 81 - 18y

8y = 81-25

8y = 56

(y = 7)

Now put y = 7 in one of the equation..

and get your answer

Answer 2

Answer:

Thanks

Step-by-step explanation:

see in the attachment.