Chemistry, asked by damini1531, 1 year ago

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Que : How many grams of slaked lime is required to prepare 143 gram bleaching powder ??

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Answers

Answered by rushi55521

1

Explanation:

Ca(ClO)2 formula

40 + 2 (35.5 +16)

40 + 103

143

n =143/143

n=1 mole

then you can easily find required answer

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