hey please answer to my question please
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use law of conservation of momentum
m1u1+ m2u2 = m1v1+m2v2
intially both bullet and gun are at rest
so left side is equal to zero
m1v1+m2v2= 0
30 v1 + 0.1× 500 = 0
velocity of gun = -50/30
= -5/3 m/s
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Q . A truck of mass 30,000 kg moves up an inclined plane of slope 1 in 100 at a speed of 30 kmph. The power of the truck is (given g = 10 ms-l) .
Answer of the above mentioned.
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