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Resistance=Resistivitylength/crosssectional area
10ohm=1.6*10to the power minus 8*length/pi*0.25
10to the power 9=1.6*length/pi*0.25
10to the power 9=1.6*length/0.785
length =785*10 to the power5 cm
The resistance will double if the diameter becomes half.
Hope it helps .
The formula is given below
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Resistance=Resistivitylength/crosssectional area
10ohm=1.6*10to the power minus 8*length/pi*0.25square
Implies 10to the power 9=1.6*length/pi*0.25square
10 to the power 9=1.6*length/0.19625
length =19625*10 to the power3 cm
The resistance will double if the diameter becomes half. The above comment is wrong along with some portion of the above answer which has been corrected here.
10ohm=1.6*10to the power minus 8*length/pi*0.25square
Implies 10to the power 9=1.6*length/pi*0.25square
10 to the power 9=1.6*length/0.19625
length =19625*10 to the power3 cm
The resistance will double if the diameter becomes half. The above comment is wrong along with some portion of the above answer which has been corrected here.
sagniksengupta067 you have written a very long answer.
Answered by
4
Resistance=Resistivitylength/crosssectional area
=> 10ohm=1.6*10^- 8*length/pi*0.25^2
=> 10^ 9=1.6*length/pi*0.25^2
=> 10 ^ 9=1.6*length/0.19625
=> length =19625*10 ^3 cm
The resistance will double if the diameter becomes half.
Hope it helps
Thanks for marking me.
welo
Similar questions
10ohm=1.6*10to the power minus 8*length/pi*0.25square
Implies 10to the power 9=1.6*length/pi*0.25square
0to the power 9=1.6*length/0.19625
length =785*10 to the power5 cm
The resistance will double if the diameter becomes half.
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