Question

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Answer 1

14) 3x+4y=16,....(1) .

xy=4.........(2)

squaring on both sides of equation (1)

we have

9x^2+16y^2+24xy=16*16=256

since (a+b)^2=a^2+b^2+2ab

9x^2+16y^2=256-24xy

=256-24*4

=256-96

=160

Answer 2

(14) 3x+4y=16

xy=4

squaring on both sides of equation .

9×^2+16y^2+24xy=16*16=256

since (a+b)^2=a^2+b+2 ab

9×^2+16^y2=256- 24 xy

=256- 24*4

=256- 96

= 160

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