Hey please help...
solve the problem
Attachments:

Answers
Answered by
1
Hope this help...........
Attachments:

Answered by
1
Since BL is the median
AL=CL=1/2 AC .............(1)
Similarly CM is the median
AM = MB = 1/2 AB ........... (2)
In triangle ABC
BC^2 = AB^2 + AC^2
In triangle BAL
BL^2 =AB^2 +AL^2
BL^2 =AB^2 +(AC/2)^2
On further little solving steps
4BL^2 =4AB^2 +AC^2
Then in triangle MAC
CM^2 =AM^2 +AC^2
Doing same process here
We get
4CM^2 =AB^2 +4AC^2
Glad to help
Similar questions