Question

Hey pls ans this ( Q. 8 )

Answer 1

Answer:

Step-by-step explanation:

According to the question the diagram is attached .

Now to show that < CPA and < DPB are congruent ,we had to first congruent the two ∆ APC and ∆ DPB.

In both the triangles

PC = PB [ Radius of the circle]

< PBD = <PCA [ Alternate angles of parallel lines]

< PDB = <PAC [ Alternate angles of parallel lines]

From AAS criterion of Congruency both the Triangles ∆CPA and ∆DPB

so,

< CPA = < DPB [by C.P.C.T.]

hence proved.

Hope it helps you

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