Question

solve the question.........

Answer 1

Your answer is given below

Answer 2

In triangle PQR <QPR is 90 degree.

So

$qr {}^{2} = pq {}^{2} + pr {}^{2}$

$(26) {}^{2} = (24) {}^{2} + pr {}^{2}$

$676 - 576 = pr {}^{2}$

$pr = 10$

Now in triangle PKR <PKR is 90 degree.

$pr {}^{2} = pk {}^{2} + kr {}^{2}$

$(10) {}^{2} = pk {}^{2} + (8) {}^{2}$

$100 - 64 = pk {}^{2}$

$pk = 6$

Thanks