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m,n are zeros of
![a {x}^{2} - 12x + c a {x}^{2} - 12x + c](https://tex.z-dn.net/?f=a+%7Bx%7D%5E%7B2%7D+-+12x+%2B+c)
Find Value of a and c if
![m + n = mn = 3 m + n = mn = 3](https://tex.z-dn.net/?f=m+%2B+n+%3D+mn+%3D+3)
HariniNivetha:
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From question,
m+n = -b/a= 12/a
m+n = 12/a = 3 ( given in question that m+n = mn = 3)
a = 4
mn = c/a = c/4 ( we found a=4)
mn = c/4 = 3 ( given in question that m+n=mn=3)
c = 12
So, a= 4, c=12
Hope you have understood.
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