Question

the amount of calcium oxide required to react completely with 852g of P4O10 is :-
CaO+P4O10=Ca3(PO4)3

Answer 1

Try gay lussac's law thisis th only suitable way to do.

Answer 2

afhahajzkajavai

$5 \frac{36 = 6.3 = {.53.12 \times \frac{?}{?} }^{?} }{?}$