Math, asked by yashita25, 11 months ago

hey pls answer this question
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Answered by aadarsharitul
2

Answer

As in every 400 years. The concept to be noted here is that, there would be 97 leap years and 303 Non-Leap years.

Any year that is a multiple of 100, will not be a leap year, unless it is also a multiple of 400.

So years like 100,200,300 are not leap years.

So 4500-3 = 4497 Days with date as 29th


aadarsharitul: As in every 400 years. The concept to be noted here is that, there would be 97 leap years and 303 Non-Leap years.
Any year that is a multiple of 100, will not be a leap year, unless it is also a multiple of 400.
So years like 100,200,300 are not leap years.
So 4500-3 = 4497 Days with date as 29th
aadarsharitul: Brainliest pls?
yashita25: yes thought of the same method thanks
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yashita25: but his method id the actual method
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Answered by JayanshJain
1

In a leap year 29th day occurs in 12 months

no of leap year in 400 years = 97

so no of times the 29th day occurs in a leap year is 97 * 12

In an ordinary year 29th day occurs in 11 months

so no of ordinary year in 400 years = 303

so no of times 29th day occurs in an ordinary year = 11*303

Total no of times 29th day occurs = 97*12+11*303= 4497

answer (A) 4497


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