HEY PLZ ANS THIS
@find the solution of this quadratic equation....
(x+2)/(x+4) - (x-1)/(x-3) = 2@
Answers
Answered by
2
2(x + 3)2 – 5x = 6
2(x + 3)2 – 5x – 6 = 6 – 6
First be sure that the right side of the equation is 0.
2(x2 + 6x + 9) – 5x – 6 = 0
2x2 + 12x + 18 – 5x – 6 = 0
2x2 + 12x – 5x + 18 – 6 = 0
2x2 + 7x + 12 = 0
Expand the squared binomial, then simplify by combining like terms.
Be sure to write the terms with the exponent on the variable in descending order.
2x2
+
7x
+
12
=
0
↓
↓
↓
a
b
c
a = 2, b = 7, c = 12
Now that the equation is in standard form, you can read the values of a, b, and c from the coefficients and constant.
Answer
2x2 + 7x + 12 = 0; a = 2, b = 7, c = 12
2(x + 3)2 – 5x – 6 = 6 – 6
First be sure that the right side of the equation is 0.
2(x2 + 6x + 9) – 5x – 6 = 0
2x2 + 12x + 18 – 5x – 6 = 0
2x2 + 12x – 5x + 18 – 6 = 0
2x2 + 7x + 12 = 0
Expand the squared binomial, then simplify by combining like terms.
Be sure to write the terms with the exponent on the variable in descending order.
2x2
+
7x
+
12
=
0
↓
↓
↓
a
b
c
a = 2, b = 7, c = 12
Now that the equation is in standard form, you can read the values of a, b, and c from the coefficients and constant.
Answer
2x2 + 7x + 12 = 0; a = 2, b = 7, c = 12
namandadhich:
please make me understand whay you have done
ohh
can u tell me first step how it cane
came
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0
sorry I don't know .
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