Question

Hey plz answer it
Urgent​

Answer 1

Answer:

1) Yes it will pass

2) <ACB = 30

<ADB= 150°

Step-by-step explanation:

1) Yes it will pass

LA+LB+LC=180° [ASP]

30+60+LC = 180

LC = 180-90 = 90

AB is diameter, we know that any point on the boundary on a circle makes 90°angle when joined with diameter.

Therefore LC must be 90°

It matches with our result, so the circle will pass through point C.

2) <ACB=<AOB/2 = 30°

<ACB = 30°

<ADB + <ACB = 180° [opposite angles of Cyclic quadrilateral]

<ADB +30°=180°

<ADB= 180°-30°

<ADB= 150°

Hope it helped you!

If it helped you then plz mark this as brainliest!

Answer 2

Answer:

1. Given,

triangle ABC where angle A = 30° and angle B = 60°

So through Angle sum property we get,

<A + <B + <C = 180°

Therefore <C = 180 - 60 - 30 = 90°

Now the next part is a bit confusing it's a statement

In a Circle, if a triangle is drawn such that one of its sides corresponds to or is placed on the diameter then its opposite angle will always be 90° and the third side will be on the circumference of the the circle

And this statement is proven from a theorem (just for your information)

This is just the converse of that statement or you can say theorem

so we have proven that the third angle C = 90°

Thus it must be on the circumference of the circle

so if we were to draw a circle through the triangle then third point will be passed .

2.  ∠AOB + ∠AOC = 180 (sum of all angle in a straight line is 180)

∠AOC = 180–60

∠AOC = 120 °

In this question ∠BAC= 90 degree because the angle in circumference of half circle should be 90 degree.

Sides AO,OB&OC are equal because these are the radius of circle.

∠OAB & ∠OBA are equal (OB=OA), now in triangle AOB

let  ∠ABO = x =  ∠ABC,

∠ ABO = ∠BAO

x+x+ ∠AOB=180 (sum all angle in triangle is 180)

2x = 180–60

x = 60 degree =  ∠ABC

∠BAC = 90°

∠ACB = 30° (Angle =  by Half angle theorem)

Hope it helps......