Question

hey plz answer these questions fast ,,,,,it is urgent ,,, both 5 and 6

Answer 1

hiiii dear____________❤️❤️❤️

good evening____________✌️✌️✌️✌️

____________________

_________________________________________________


Q. 5

If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5

Prime factorisation of 6n = (2 ×3)n

It can be observed that 5 is not in the prime factorisation of 6n.

Hence, for any value of n, 6n will not be divisible by 5.

Therefore, 6n cannot end with the digit 0 for any natural number n.






Q. 6


Numbers are of two types - prime and composite. Prime numbers can be divided by 1 and only itself, whereas composite numbers have factors other than 1 and itself. 

It can be observed that 

7 × 11 × 13 + 13 = 13 × (7 × 11 + 1) = 13 × (77 + 1) 

= 13 × 78 

= 13 ×13 × 6 

The given expression has 6 and 13 as its factors. Therefore, it is a composite number. 

7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 = 5 ×(7 × 6 × 4 × 3 × 2 × 1 + 1) 

= 5 × (1008 + 1) 

= 5 ×1009 

1009 cannot be factorised further. Therefore, the given expression has 5 and 1009 as its factors. Hence, it is a composite number.