Question

HEY PLZ DO NO. 4TH I'M NOT GETTING ANSWER....

Answer 1

Let the ten's digit number be x.

Let the one's digit number be y.

Therefore the original number is 10x + y.

On interchanging the digits, we get 10y + x.

Given that sum of two digit number is 3.

x + y = 3  ----- (1) 


Given that The number obtained by interchanging the digits is 9 less than the original number.

10y + x = 10x + y - 9

9x - 9y = 1

x - y = 1  -------- (2)


On solving (1) & (2), we get

x + y = 3

x - y = 1

-------------

2x = 4

x = 2.


Subsitute x = 2 in (1), we get

x + y = 3

2 + y = 3

y = 1.


Therefore the original number is 10x + y = 10(2) + 1

                                                                 = 21.


Hence, the original number is 21.


Hope this helps!

Answer 2

Hi,


Please see the attached file!

Thanks