Question

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Answer 1

Answer:

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Answer 2

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UR\:QUESTION:-a godown measures 40m×25m×15m.find the maximum number of wooden crates each measuring 1.5m×1.25m×0.5m.that can be stored in the godown

$\huge {\mathbf {Q.}}}$

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URANSWER ✓

$\Large\underline\bold{given}$

$\sf\dashrightarrow godown \:is\: in \:the \:shape\: of \:cuboid \:measuring\: sides \:40m \times 25m \times 15m$

$\sf\dashrightarrow wooden crates measuring 1.5m \times 1.25m \times 0.5m$

$\Large\underline\bold{diagram,}$

$\setlength{\unitlength}{5mm}\begin{picture}(5,5)\multiput(0,0)(0,6){2}{\multiput(0,0)(2,1){2}{\line(1,0){12}}\multiput(0,0)(12,0){2}{\line(2,1){2}}}\multiput(0,0)(12,0){2}{\multiput(0,0)(2,1){2}{\line(0,1){6}}}\end{picture}$

$\Large\underline\bold{solution,}$

$\sf\implies volume\:of\:godown(cuboid)= L \times B \times H$

$\sf\implies 40m \times 25m \times 15m$

$\sf\implies volume\:of\:wooden\:crate(cuboid)= L \times B \times H$

$\sf\implies 1.5m \times 1.25m \times 0.5m$

$\sf\therefore to\:find \:no\:of\:crates = \dfrac{volume\:of\:godown}{volume\:of\:wooden\:crates}$

$\sf\implies to\:find \:no\:of\:crates = \dfrac{40m \times 25m \times 15m}{1.5m \times 1.25m \times 0.5m}$

$\sf\implies to\:find \:no\:of\:crates = \cancel \dfrac{40m \times 25m \times 15m}{1.5m \times 1.25m \times 0.5m}$

$\sf\dashrightarrow 16000m^3$

$\huge{\fbox{the\:max. \:no. \:of\: wooden\:crates=16000m^3}}$

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