Question

Hey plzz help me.....

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Express Sin A in the term of Sec A

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Answer 1

Hey here is your answer:

Step-by-step explanation:

sinA=1/cosecA

sinA=1/secA/(√sec squareA -1)

sinA=√sec squareA -1/secA

I hope you can understand

Answer 2

Answer:

sin A = √ 1-cos²A

= √ 1-1/sec²A

= √ (sec²A-1) /sec²A

I hope I am correct