Question

hey solve ....find the value of n

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Answer 1

$\frac{ {3}^{2n} \times {3}^{2 + n} - {3}^{3n} }{ {3}^{15} \times {2}^{3} } = {3}^{ - 3} \\ \frac{ {3}^{2n + 2 + n} - {3}^{3n} }{ {2}^{3} } = {3}^{15} \times {3}^{ - 3} \\ \frac{ {3}^{3n + 2} - {3}^{3n} }{8} = {3}^{12} \\ \frac{ {3}^{3n} ( {3}^{2} - 1) }{8} = {3}^{12} \\ \frac{ {3}^{3n}(9 - 1) }{8} = {3}^{12} \\ \frac{ {3}^{3n} \times 8 }{8} = {3}^{12} \\ {3}^{3n} = {3}^{12} \\ compare \: the \: powers \\ 3n = 12 \\ n = \frac{12}{3} \\ n = 4 \: \: \: \: answer$