Question

hey !!!!!!!!!!!!!!




solve it...

it is of 9th class algebra....


maharashtra board......



solution dedo yrr​

Answer 1

Solution for the equation is x = -12 and y = -17 and fraction is $\frac{x}{y} = \frac{12}{17}$.

• We solve for equation 1 first :

Numerator is multiplied by 5 and 3 is subtracted from the denominator then the fraction obtained is 3.

$\frac{5x}{y-3} = 3$

• We solve for equation 2 now:

Numerator is increased by 5 and the denominator is halved then the fraction is equal to 2.

$\frac{x+5}{\frac{y}{2} } = 2$

• Now we write equation 1 in standard form by solving the equation:

5x = 3y - 9

5x - 3y = -9 .....(Equation 1)

• Now we write equation 2 in standard form by solving the equation:

2x + 10 = 2y

2x - 2y = 10

x - y = 5   .....(Equation 2)

• Solving both equations :

Multiplying equation 2 by 3

3x - 3y =15  .....(Equation 3)

• Solving equation 1 and 3 by subtracting 2 from 1

2x = -24

x = -12

• now substituting value of x in equation 2

-12 -y = 5

y = -17

• Solution for the equations is x = -12 and y = -17
• Fraction given is $\frac{-12}{-17}$

$\frac{x}{y} = \frac{12}{17}$

Answer 2

Answer:

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