Question

hey...
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solve it ...
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Spammers stay away...​

Answer 1

a^-n=1/a^n

So,125=5^3

5^3*5^7*6^5/3^5*10^5

=5^3*5^7*(3*2)^5/3^5*(5*2)^5

A^m*A^n=A^m+n

A^m/A^n=A^m-n

5^(3+7-5+5)*3^(5-5)*2^(5-5)

=5^10*3^0*2^0

A^0=1

=5^10*1*1

=5^10

Answer 2

Answer:

...... 3125

Step-by-step explanation:

=>3^-5x10^-5x125/5^-7x6^-5

=>3^-5x10^-5x125/5^-7x6^-5=>5^7x6^5x125/3^5x10^5

=>3^-5x10^-5x125/5^-7x6^-5=>5^7x6^5x125/3^5x10^5=>78125x7776x125/243x100000

=>3^-5x10^-5x125/5^-7x6^-5=>5^7x6^5x125/3^5x10^5=>78125x7776x125/243x100000=>75937500000/243x100000

=>3^-5x10^-5x125/5^-7x6^-5=>5^7x6^5x125/3^5x10^5=>78125x7776x125/243x100000=>75937500000/243x100000=>759375/243

=>3125

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