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Given,
8x + 5y = 60
5x + 5y = 30
(-) --------------------
3x = 30
x= 10
substituting the value of x to find y,
5y = 30- 5x
5y = -20
y= -4
Alternative method:
8x + 5y = 60
5y = 60 - 8x
y= 60-8x/ 5..........(a)
5x+ 5y= 30
5y= 30-5x
y= 30-5x/5.........(b)
equating a and b,
60-8x/5 = 30 -5x/5
60- 8x= 30-5x
30= 3x
x= 10
substituting the value of x to find y,
y = 30- 50/5 = -4
thus ,
X= 10
Y= -4
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