Question

HEY
$8x + 5y = 60\\ 5x + 5y = 30 \\ find \: x \: and \: y \:$
^_^​

Answer 1

ANSWER:

Given

8x + 5y = 60

Assuming as equation ( 1 )

5x + 5y = 30

Assuming as equation ( 2 )

Subtracting Equation ( 1 ) - ( 2 )

8x + 5y = 60

- (5x + 5y) = 30

3x = 30

→ 3x = 30

→ x = 10

Substituting x = 10

In equation ( 1 )

→ 8(10) + 5y = 60

→ 80 + 5y = 60

→ 5y = - 20

→ y = -20/5

→ y = -4

VERIFICATION:

Let us substitute the values of x & y in equation 1

→ 8(10) + 5(-4) = 60

Taking LHS

→ 80 - 20

→ 60

LHS = RHS

Hence verified

Hence x = 10 and y = - 4

Answer 2

Step-by-step explanation:

$\underline{\underline{\bold{Answer :}}}$

$\Longrightarrow8x + 5y = 60 - - - - - - - - - (1) \\ \Longrightarrow5x + 5y = 30 - - - - - - - - - (2)$

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$\hookrightarrow | | by \: subtracting \: equation \: 1 \: with \: equation \: 2 \: \\ we get | |$

$\star{\underline{ \underline{\red{we \: get :}}}}$

$\longrightarrow8x + 5y - (5x + 5y) = 60 - 30 \\ \longrightarrow8x + 5y - 5x - 5y = 30 \\ \longrightarrow3x = 30 \\ \longrightarrow x =10$

$\star{ \fbox{\underline{\pink{ \: value \: of \: x = 10}}}} \\ \star{\fbox{\underline{\pink{value \: of \: y \hookrightarrow y = \frac{60 - 8x}{5} = \frac{60 - 80}{5} = - 4}}}}$

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VERIFICATION OF THE BOTH ABOVE VALUES:-

a) FOR VERIFICATION WE NEED TO PUT BOTH THE ABOVE VALUES OF X AND Y IN ANY OF THE ONE EQUATION:--

b) IF LHS = RHS OF THE EQUATION THEN THE VALUES CALCULATED ABOVE WILL BE CORRECT

$\Longrightarrow 8x + 5y = 60$

NOW PUTTING THE VALUES OF X AND Y WE GET:-

$\Longrightarrow \: lhs =( 8 \times 10 )+ (5 \times - 4) = 80 - 20 = 60. \\ \Longrightarrow \: rhs = 60$

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HENCE ABOVE VALUE OF X AND Y ARE CORRECT AND THEY ARE VERIFIED TOO.

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