Question

HEY####

The energy density $\frac{u}{V}$ of an ideal gas is related to its pressure 'P' as..

a). $\frac{u}{V}$ =3P
b). $\frac{u}{V}$= $\frac{3}{2}$P
c). $\frac{u}{V}$= $\frac{1}{3}$P
d). $\frac{u}{V}$= $\frac{2}{3}$P.....

DIG out the ans fast...


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Answer 1

$\huge{\mathbb\purple{ANSWER}}$

>>>Given=> ENERGY density relation=>

u = $\frac{E}{V}$

where E = energy.

V =volume...

in general dimensions of pressure and energy density are same...

Equating==>

PV = $\frac{2}{3}$u

P = $\frac{2u}{3V}$

$\frac{3}{2}$P = $\frac{u}{V}$

$\frac{u}{V}$ = $\frac{3}{2}$P...

HENCE,, option 'b' is correct.....

$\huge{\mathbb\blue{@\:HOWNER}}$

Answer 2

B)

This is the correct ans.

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