Question

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Answer 1

Question :

In the following equation :

$\sf\:Cl0^{-1}_3+6H^{+}+X\rightarrow\:Cl^{-1}+3H_2O$

Then find X

Solution :

Given Equation :

$\sf\:Cl0^{-1}_3+6H^{+}+X\rightarrow\:Cl^{-1}+3H_2O$

Here, We observe that no of all the atoms on both sides are equal.

$\begin{array}{| c | c | c |}\cline{1-3} No\:of\:atoms & In\:reactant & In\:product\\\cline{1-3} Cl & 1 & 1\\\cline{1-3} O & 3 & 3\\\cline{1-3} H & 6 & 6\\\cline{1-3}\end{array}$

Now , In Reaction :

Here ,$\sf\:Cl0^{-1}_3+6H^{+}+X\rightarrow\:Cl^{-1}+3H_2O$

In left hand side :

$\sf\:Cl0^{-1}_3+6H^{+}+X$

Charge on $\sf\:ClO^{-1}_3$ is -1

and charge on X be let x

So, net charge in left hand side is -1+x

In Right hand side :

$\sf\:Cl^{-1}+3H_2O$

Charge on Cl is -1

and charge on $\sf\H_2O$ is 0

So, Net charge in right hand side is -1

Balance net charge on both sides

Charge in left hand side = Charge on left hand side.

⇒ 5+ x = -1

⇒x =-6

Therefore, X is $\sf\:6e^{-}$

Correct option b) $\sf\:6e^{-}$

$\rule{200}2$

More About the topic :

• Balancing of redox Equations :

There are two methods of balancing redox equations:

1. Oxidation number method
2. Ion electron method.