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carbon and oxygen combined together in different ratios of 42.9%, 27.3% respectively. prove that whether above reaction follows law of multiple proportion...
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Solution:
Compound – 1:
Let us consider 100 g of compound – 1
Mass of carbon = 42.9 g
Mass of oxygen = 100 g – 42.9 g = 57.1 g
Thus, 42.9 g of carbon combines with 57.1 g of oxygen.
∴ 1 g of carbon combines with 57.1/42.9 = 1.33 g of oxygen. …………………….. (1)
Compound – 2:
Let us consider 100 g of compound – 2
Mass of carbon = 27.3 g
Mass of oxygen = 100 g – 27.3 g = 72.7 g
Thus, 27.3 g of carbon combines with 72.7 g of oxygen.
∴ 1 g of carbon combines with 72.7/27.3 = 2.66 g of oxygen. …………………….. (2)
From statements (1) and (2), the ratio of different masses of oxygen combining with fixed mass of carbon (1 g) is 1.33 : 2.66 i.e. 1 : 2, which is simple whole number ratio. Thus, the data illustrate the law of multiple proportions.
Compound – 1:
Let us consider 100 g of compound – 1
Mass of carbon = 42.9 g
Mass of oxygen = 100 g – 42.9 g = 57.1 g
Thus, 42.9 g of carbon combines with 57.1 g of oxygen.
∴ 1 g of carbon combines with 57.1/42.9 = 1.33 g of oxygen. …………………….. (1)
Compound – 2:
Let us consider 100 g of compound – 2
Mass of carbon = 27.3 g
Mass of oxygen = 100 g – 27.3 g = 72.7 g
Thus, 27.3 g of carbon combines with 72.7 g of oxygen.
∴ 1 g of carbon combines with 72.7/27.3 = 2.66 g of oxygen. …………………….. (2)
From statements (1) and (2), the ratio of different masses of oxygen combining with fixed mass of carbon (1 g) is 1.33 : 2.66 i.e. 1 : 2, which is simple whole number ratio. Thus, the data illustrate the law of multiple proportions.
Sudo1:
thanks dear for helping me
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